Q: In the given circuit the current through Zener Diode is close to :

From the given diagram,\${R_1} = 500\Omega \$\${R_2} = 1500\Omega \$\${V_2} = 10V\$As the resistors are in parallel, the potential difference across the \$1500\Omega \$ will also be 10 V.The potential difference across the \$500\Omega \$ will be\${V_1} = 12 - 10 = 2V\$According to ohm’s law,\$V = IR\$\$ \Rightarrow I = \dfrac{V}{R}\$Current across the \$500\Omega \$ is\$ \Rightarrow {I_1} = \dfrac{{{V_1}}}{{{R_1}}} = \dfrac{2}{{500}} = 4 \times {10^{ - 3}}A\$Current across the \$1500\Omega \$ is\$ \Rightarrow {I_2} = \dfrac{{{V_2}}}{{{R_2}}} = \dfrac{{10}}{{1500}} = 6.66 \times {10^{ - 3}}A\$From above calculations, \${I_1} < {I_2}\$ (Not possible case)So the potential difference across Zener diode will never reach to breakdown voltage. The current flows in the Zener diode only when the applied reverse voltage reaches breakdown voltage. Therefore, the current flowing through the Zener diode is 0 mAHence, Option (D) is the correct answer

Q: The truth table given in figure represents:

OR gate has the property that output is one when any one of the inputs is one and zero only when all inputs are zero. From the truth table, it can be seen that the above two properties are satisfied.

Q: An experiment is performed to determine the \$I - V\$ characteristics of a Zener diode, which has a protective resistance of \$R = 100 \Omega\$, and a maximum power of dissipation rating of \$1 W\$. The minimum voltage range of the DC source in the circuit is

The circuit diode for a zener diode with a protective resistance is shown.Applying KVL,\$V = iR + V_D\$\$V_D = V - iR = V-100i\$Maximum power dissipated across the zener diode is given by:\$P = V_Di = (V-100i)i = 1\$\$\therefore 100i^2 - Vi + 1 \geq 0 \$Current should be real, hence determinant is greater than zero.\$\therefore V^2 > 400\$ \$V >20 V\$

Q: The combination of gates shown below yields

\$\textbf{Hint}\$:In the given figure NAND gate is a combination of AND and NOT gate. Use truth table and Demorgan's theorem.\$\textbf{Step 1:Truth table for NAND Gate}\$The output of AND gate is connected to the input of NOT gate. So, the output of NAND gate is opposite to AND gate. We know the truth table of NAND gate is as follows where A and B are inputs, Y is the output:A B Y0 0 10 1 11 0 11 1 0\$\textbf{Step2:Apply DeMorgan's theorem}\$Here in the figure the input A and B are connected to a NOT gate and the output of both NOT gate is given to a NAND gate.\$X=\overline{\bar{A}.\bar{B}}\$ \$(1)\$Let us apply Demorgan's rule we get\$\overline{A.B}=\bar{A}+\bar{B}\$Let is substitute Demorgan's rule in equation \$(1)\$ we get\$X=\bar{\bar{A}}+\bar{\bar{B}}=A+B\$The resultant is an OR gate. Thus option A is correct.

Question 1

In the given circuit the current through Zener Diode is close to :

Accepted Answer

From the given diagram,${R_1} = 500\Omega $${R_2} = 1500\Omega $${V_2} = 10V$As the resistors are in parallel, the potential difference across the $1500\Omega $ will also be 10 V.The potential difference across the $500\Omega $ will be${V_1} = 12 - 10 = 2V$According to ohm&#8217;s law,$V = IR$$ \Rightarrow I = \dfrac{V}{R}$Current across the $500\Omega $ is$ \Rightarrow {I_1} = \dfrac{{{V_1}}}{{{R_1}}} = \dfrac{2}{{500}} = 4 \times {10^{ - 3}}A$Current across the $1500\Omega $ is$ \Rightarrow {I_2} = \dfrac{{{V_2}}}{{{R_2}}} = \dfrac{{10}}{{1500}} = 6.66 \times {10^{ - 3}}A$From above calculations, ${I_1} < {I_2}$ (Not possible case)So the potential difference across Zener diode will never reach to breakdown voltage. The current flows in the Zener diode only when the applied reverse voltage reaches breakdown voltage. Therefore, the current flowing through the Zener diode is 0 mAHence, Option (D) is the correct answer

Question 2

The truth table given in figure represents:

Accepted Answer

OR gate has the property that output is one when any one of the inputs is one and zero only when all inputs are zero. From the truth table, it can be seen that the above two properties are satisfied.

Question 3

An experiment is performed to determine the $I - V$ characteristics of a Zener diode, which has a protective resistance of $R = 100 \Omega$, and a maximum power of dissipation rating of $1 W$. The minimum voltage range of the DC source in the circuit is

Accepted Answer

The circuit diode for a zener diode with a protective resistance is shown.Applying KVL,$V = iR + V_D$$V_D = V - iR = V-100i$Maximum power dissipated across the zener diode is given by:$P = V_Di = (V-100i)i = 1$$\therefore 100i^2 - Vi + 1 \geq 0 $Current should be real, hence determinant is greater than zero.$\therefore V^2 > 400$ $V >20 V$

Question 4

Identify the gate and match A, B, Y in bracket to check.

Accepted Answer

The given diagrams involve 2 gates.The first 1 is an AND gate followed by a NOT Gate, with the compliment of the output of first gate used as an input to the other gate which is NAND gate as NOT gate.We consider the 4 combinations$A = 1 , B = 1,  AB = 1,  (AB)' = 0, \bar{AB}=1, Y = 0$$A = 1 , B = 0,  AB = 0,  (AB)' = 1, \bar{AB}=0, Y = 1$$A = 1 , B = 0,  AB = 0,  (AB)' = 1, \bar{AB}=0, Y = 1$$A = 0 , B = 0,  AB = 0,  (AB)' = 1, \bar{AB}=0, Y = 1$The above configuration represents that of an AND gate.

Question 5

The combination of gates shown below yields

Accepted Answer

$\textbf{Hint}$:In the given figure NAND gate is a combination of AND and NOT gate. Use truth table and Demorgan's theorem.$\textbf{Step 1:Truth table for NAND Gate}$The output of AND gate is connected to the input of NOT gate. So, the output of NAND gate is opposite to AND gate. We know the truth table of NAND gate is as follows where A and B are inputs, Y is the output:A   B   Y0   0   10    1    11     0   11     1    0$\textbf{Step2:Apply DeMorgan's theorem}$Here in the figure the input A and B are connected to a NOT gate and the output of both NOT gate is given to a NAND gate.$X=\overline{\bar{A}.\bar{B}}$     $(1)$Let us apply Demorgan's rule we get$\overline{A.B}=\bar{A}+\bar{B}$Let is substitute Demorgan's rule in equation $(1)$ we get$X=\bar{\bar{A}}+\bar{\bar{B}}=A+B$The resultant is an OR gate. Thus option A is correct.

Question 6

If a,b,c,d are inputs to a gate and x is its output then as per the following time graph the gate is:

Accepted Answer

From the waveforms, output is 0 only when all four inputs are 0. When, any one of the inputs is 1, then the output is 1. This is valid only for OR gate.

Question 7

To get an output of 1. from the circuit shown in figure the input must be

Accepted Answer

To get final output as 1, the output of OR gate must be 1 and C must be 1.So, a = 1, b =0 or a=0, b=1.

Question 8

Carbon, silicon and germanium have four valence electrons each. At room temperature which one ofthe following statements is most appropriate ?

Accepted Answer

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Question 9

In the given circuit, the current through zener diode is:

Accepted Answer

the current through 500 ohm resistor is 0.01 ampere as voltage across is 5V.the current through 1500 ohm resistor is 0.0067 ampere so the current through zener diode is difference in current through these resistors . so the current is $ 0.01-0.0067=0.0033 $ampere .On converting to mA we get Current through zener diode = 3.3 mAso the correct answer is B.

Semiconductor Electronics Materials Devices And Simple Circuits

Physics
4419 Views

In the given circuit the current through Zener Diode is close to :

The truth table given in figure represents:

An experiment is performed to determine the $I - V$ characteristics of a Zener diode, which has a protective resistance of $R = 100 Ω$ , and a maximum power of dissipation rating of $1 W$ . The minimum voltage range of the DC source in the circuit is

Identify the gate and match A, B, Y in bracket to check.

The combination of gates shown below yields

If a,b,c,d are inputs to a gate and x is its output then as per the following time graph the gate is:

To get an output of 1. from the circuit shown in figure the input must be

Carbon, silicon and germanium have four valence electrons each. At room temperature which one ofthe following statements is most appropriate ?

In the given circuit, the current through zener diode is:

Semiconductor Electronics Materials Devices And Simple Circuits

Physics 4419 Views

In the given circuit the current through Zener Diode is close to :

The truth table given in figure represents:

An experiment is performed to determine the I−V characteristics of a Zener diode, which has a protective resistance of R=100Ω, and a maximum power of dissipation rating of 1W. The minimum voltage range of the DC source in the circuit is

Identify the gate and match A, B, Y in bracket to check.

The combination of gates shown below yields

If a,b,c,d are inputs to a gate and x is its output then as per the following time graph the gate is:

To get an output of 1. from the circuit shown in figure the input must be

Carbon, silicon and germanium have four valence electrons each. At room temperature which one ofthe following statements is most appropriate ?

In the given circuit, the current through zener diode is:

Physics
4419 Views

An experiment is performed to determine the $I - V$ characteristics of a Zener diode, which has a protective resistance of $R = 100 Ω$ , and a maximum power of dissipation rating of $1 W$ . The minimum voltage range of the DC source in the circuit is