Work Energy And Power

Q: The force on a particle as the function of displacement x(in x-direction) is given by F=10+0.5x The work done corresponding to displacement of particle from x=0 to x=2 unit is?

Given that F=10+0.5x Work done corresponding to the particle from x=0 to x=2 unit is, W= \int_{0}^{2} F.dx= \int_{0}^{2} (10+0.5x)dx= [10x+ \dfrac{0.5x^2}{2}]_0^2= 20+1= 21 J

Question

The force on a particle as the function of displacement x(in x-direction) is given by $F = 10 + 0.5 x$
The work done corresponding to displacement of particle from $x = 0$ to $x = 2$ unit is?

Work Energy And Power

Physics 215 Views

The force on a particle as the function of displacement x(in x-direction) is given by F=10+0.5x The work done corresponding to displacement of particle from x=0 to x=2 unit is?

Physics
215 Views

The force on a particle as the function of displacement x(in x-direction) is given by $F = 10 + 0.5 x$
The work done corresponding to displacement of particle from $x = 0$ to $x = 2$ unit is?