Q2
In a reaction vessel 0.184 g of NaOHis required to be added for completing the reaction. How many millilitre of 0.150 M NaOH should be added for this requirement ? can see do it like this: .184 g of naoh =0.046 moles
0.15moles in 1000 liters so 0.046 moles with
l be 1000.15* 0.046