Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

0.22 240 Calculate the extent of hydrolysis of 0.005 M K Cro. [K, = 3.1 x 10-7 for H,Cro. (It is essentially strong for first ionization). 1 =0.26 5x3.1 lo What is the hydrolysis

Open in App

Solution

Verified by Toppr

Was this answer helpful?

0

Similar Questions

Q1

Calculate the extent of hydrolysis of

0.005 M

K_{2} C r O_{4}

.

[K_{2} = 3.1 \times 10^{- 7}

for

K_{2} C r O_{4};

It is essentially strong for first ionization].

View Solution

Q2

Calculate the extent of hydrolysis of $$0.005M$$ $${ K }_{ 2 }Cr{ O }_{ 4 }.{ K }_{ 2 }=3.1\times { 10 }^{ -7 }\quad $$ for $${ H }_{ 2 }Cr{ O }_{ 4 }$$. ($${ H }_{ 2 }Cr{ O }_{ 4 }$$ is strong for first ionisation and $${K}_{1}=1.6$$)

View Solution

Q3

Calculate the extent of hydrolysis of

0.005 M K_{2} C r O_{4} [K_{2} = 3.1 \times 10^{- 7}

for

H_{2} C r O_{4}]

.

View Solution

Q4

$$0.1M$$ $$NH_4OH$$ is $$1\%$$ ionized. Find the extent of hydrolysis of $$0.1M$$ $$NH_4Cl$$.

View Solution

Q5

The ionization constant of nitrous acid is $4.5 \times 10^{- 4}$ . Calculate the pH of 0.04 M sodium nitrite solution and also its degree of hydrolysis.

View Solution