Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Chemistry
Dalton's Law of Partial Pressures
Question

0.5 mole of each of H, SO2 and CH4, are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be:
  1. P(CH4)>P(SO2)>P(H2)
  2. P(H2)>P(CH4)>P(SO2)
  3. P(H2)>P(SO2)>P(CH4)
  4. P(SO2)>P(CH4)>P(H2)

A
P(CH4)>P(SO2)>P(H2)
B
P(H2)>P(CH4)>P(SO2)
C
P(SO2)>P(CH4)>P(H2)
D
P(H2)>P(SO2)>P(CH4)
Open in App
Solution
Verified by Toppr

SO2 Molar mass= 32+32=64g/mol
CH4 Molar mass= 12+4=16g/mol
H2 Molar mass= 2×1=2g/mol
Rate of diffusion is inversely related to molecular weight. Lighter the gas, more is the diffusion. The rate of diffusion is given by,
rH2>rCH4>rSO2
Hence the order of partial pressure will be
PSO2>PCH4>PH2

Was this answer helpful?
5
Similar Questions
Q1
0.5 mole of each of H, SO2 and CH4, are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be:
View Solution
Q2
0.5 mol of each of H2,SO2 and CH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be:

View Solution
Q3
0.5 mole of each H2,SO2 and CH4 are kept in a container. A hole was made in the container. After 3 hours, decreasing order of partial pressures of gases in the container will be:
View Solution
Q4
A vessel contains 0.5 mole each of SO2,H2 and CH4. Its outlet was made open and closed after sometime. Thus, order of partial pressure will be:
View Solution
Q5
A vessel contains 0.5 mole each of SO2,H2 and CH4. Its outlet was made open and closed after some time. Thus, the order of partial will be:
View Solution