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(1) AD bisects DC 3/ Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of APQR (see Fig. 7.40). Show that: (1) A ABME APQN (i) A ABC=APQR

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Similar Questions

Q1

Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of $$\triangle PQR$$. Show that :
(i) $$\triangle ABM \cong \triangle PQN$$
(ii) $$\triangle ABC \cong \triangle PQR$$

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Q2

Two sides

A B

and

B C

and median

A M

of one triangle

A B C

are respectively equal to side

P Q

and

Q R

and median

P N

of

Δ P Q R

(see figure). Show that
(i)

Δ A B M = Δ P Q N

(ii)

Δ A B C = Δ P Q R

View Solution

Q3

In given figure two sides

A B, B C

and median

A M

of one triangle

A B C

are respectively equal to sides

P Q

and

Q R

and median

P N

of

△ P Q R

. Show that:

△ A B M ≅ △ P Q N

View Solution

Q4

Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ΔPQR (see the given figure). Show that:

Δ A B M ≅ Δ P Q N

View Solution

Q5

Question 3 (i)
Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ΔPQR (see the given figure). Show that:

Δ A B M ≅ Δ P Q N

View Solution