1 atom of Iron -Fe- weighs - grams-Molecular Weight of Fe - 56 g-mole-9-3-times- 10-23- 6-3-times- 10-23- 4-3-times- 10-23-5-3-times- 10-23-

Question

Toppr Admin · Accepted Answer

For Fe atoms molar mass -xA0-56 g-mole-1 mole -6-023-xD7-1023 atoms56 g -xA0-6-023-xD7-1023 atoms1 atom weighs -566-023-xD7-1023 g -9-3-xD7-10-x2212-23 g

1 atom of Iron $(F e)$ weighs ______ grams.
(Molecular Weight of $F e = 56$ g/mole)

$9.3 \times 10^{- 23}$
$6.3 \times 10^{- 23}$
$4.3 \times 10^{- 23}$
$5.3 \times 10^{- 23}$

For $F e$ atoms molar mass $= 56$ g/mole.

$1$ mole $= {6.023 \times 10}^{23}$ atoms

$56$ g $= {6.023 \times 10}^{23}$ atoms

$1$ atom weighs = $\frac{56}{{6.023 \times 10}^{23}}$ g $= 9.3 \times 10^{- 23}$ g

1 atom of Iron (Fe) weighs ______ grams.(Molecular Weight of Fe=56 g/mole)9.3×10−23 6.3×10−23 4.3×10−235.3×10−23

For Fe atoms molar mass = 56 g/mole.1 mole =6.023×1023 atoms56 g = 6.023×1023 atoms1 atom weighs =566.023×1023 g =9.3×10−23 g

1 atom of Iron $(F e)$ weighs ______ grams.
(Molecular Weight of $F e = 56$ g/mole)

$9.3 \times 10^{- 23}$
$6.3 \times 10^{- 23}$
$4.3 \times 10^{- 23}$
$5.3 \times 10^{- 23}$

For $F e$ atoms molar mass $= 56$ g/mole.

$1$ mole $= {6.023 \times 10}^{23}$ atoms

$56$ g $= {6.023 \times 10}^{23}$ atoms

$1$ atom weighs = $\frac{56}{{6.023 \times 10}^{23}}$ g $= 9.3 \times 10^{- 23}$ g