1g mixture of equal number of mole of Li2CO3 and other metal carbonate (M2CO3) required 21.6mL of 0.5NHCl for complete neutralisation reaction. What is the approximate atomic mass of the other metal?
25
23
51
118
A
25
B
51
C
23
D
118
Open in App
Solution
Verified by Toppr
Was this answer helpful?
5
Similar Questions
Q1
1 g of a mixture containing equal number of moles of carbonate of alkali metals required 44.4 mL of 0.5 NHCl for complete reaction. The atomic mass of one metal is 7, the atomic mass of other metal is :
View Solution
Q2
1g of a metal required 50mL of 0.5NHCl to dissolve it. The equivalent mass of the metal is:
View Solution
Q3
1g of metal carbonate neutralises completely 200mL of 0.1NHCl. The equivalent weight of metal carbonate is:
View Solution
Q4
1g of metal carbonate neutralises completely 200mL of 0.1NHCl. The equivalent weight of metal carbonate is:
View Solution
Q5
1.0g carbonate of a metal was dissolved in 50mLN/2HCl solution. The resulting liquid required 25mL of N/5NaOH solution to neutralise it completely. Calculate the equivalent mass of the metal carbonate.