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Question

1. If x:y=3:5,find the ratio 3x+4y:8x+5y.
2. If x:y=8:9 find the ratio (7x4y):3x+2y
3. If two numbers are in the ratio 6:13 and their l.c.m. is 312, find the numbers.
4. What should be added to each term of the ratio 7:13 so that the ratio becomes 2:3

Solution
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1). Let x=3λ

y=5λ

So, 3x+4y3x+5y=3(3λ)+4(5λ)8(3λ)+5(5λ)=9λ+20λ24λ+25λ

=29λ49λ=29:49

2). Let x=8λ

y=9λ

So, 7x4y3x+2y=7(8λ)4(9λ)3(8λ)+2(9λ)=56λ36λ24λ+18λ=20λ42λ=1021=10:21

3). Let the numbers be 6x and 13x

Now, Since x is a common multiple

LCM of 6x and 13x=13×6×x

=78x

Now, 78x=312x=31278=4

Hence, Required numbers are 6x=6×4=24

13x=13×4=52

4). Let the number to be added by y

Such that, 7+y13+y=21321+3y=26+2yy=5

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Similar Questions
Q1
1. If x:y=3:5,find the ratio 3x+4y:8x+5y.
2. If x:y=8:9 find the ratio (7x4y):3x+2y
3. If two numbers are in the ratio 6:13 and their l.c.m. is 312, find the numbers.
4. What should be added to each term of the ratio 7:13 so that the ratio becomes 2:3
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Q2
If x:y=3:5 find ratio 3x+4y:8x+5y
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Q3
If x : y = 3 : 5, find the ratio 3x + 4y : 8x + 5y.
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Q4
What should be added to each term of the ratio 7 : 13 so that the ratio becomes 2 : 3
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Q5
If two numbers are in the ratio 6:13 and their L.C.M is 312, find the numbers.
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