Question

1 mole of $PC{l}_3$ and 1 mole of $PC{l}_5$ is taken in a vessel of 10 L capacity maintained at 400 K.At equilibrium, the moles of $C{l}_2$ is found to be $4\times {10}^{-3}$

• A. $K_c$ for the reaction : $PC{l}_5\left(g\right)$$\rightleftharpoons$$PC{l}_3\left(g\right)+C{l}_2\left(g\right)$ is $4\times {10}^{-4}$ M.
• B. $K_p$ for the reaction : $PC{l}_3+C{l}_2\left(g\right)$$\rightleftharpoons$$PC{l}_5\left(g\right)+\left(g\right)$ is $4\times {10}^{-4}\times (0.082\times 400)$ atm
• C. If $PC{l}_3\left(g\right)$ is added to the equilibrium mixture, $K_p$ at the new equilibrium becomes greater than the $K_p$ at old equilibrium.
• D. After equilibrium is achieved, moles of $PC{l}_3$ is doubled and moles of $C{l}_2$ is halved simultaneously then the partial pressure of $PC{l}_5$ remains unchanged.

Answer 1

Answer: (A), (B)

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