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Question

10 g of ice at 0C absorbs 5460 J of heat energy to melt and change to water at 50C. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200Jkg1K1.
  1. 2168Jg1
  2. 336Jg1
  3. 21.68Jg1
  4. 43.36Jg1

A
2168Jg1
B
21.68Jg1
C
336Jg1
D
43.36Jg1
Solution
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Heat absorb =mL+mc×(T0)
5460=10×L+10×4.2×50
L=336Jg1

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