Question

$10$ ml $NNaOH$ will be neutralized by:

• A. $10ml$ $N{H}_2{SO}_4$
• B. $20ml$ $N{H}_2{SO}_4$
• C. $20ml$ $M{H}_2{SO}_4$
• D. $10ml$ $M{H}_2{SO}_4$

Answer 1

Answer: (A)

In chemistry, neutralization is a chemical reaction in which an acid and a base react quantitatively with each other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in solution. In the reaction, the amount of base added must moreover equal the amount of acid present initially. This amount of base is said to be the equivalent amount. In a titration of an acid with a base, the point of neutralization can also be called the equivalence point The quantitative nature of the neutralization reaction is most conveniently expressed in terms of the concentration of acid and alkali. At the equivalence point:

volume (acid) × concentration ( hydrogen ions from dissociation) is equal to volume (base) × concentration (hydroxyl ions). So $10mlN$ sodium hydroxide will be neutralized by $10mlN$ sulphuric acid.