Question

100 gm of ice at $0^{{}_{-}^0}C$ is mixed with 100 g of water at ${100}^{{}_{-}^0}C$. What will be the final temperature of the mixture?

• A. ${20}^{{}_{-}^0}C$
• B. ${30}^{{}_{-}^0}C$
• C. ${40}^{{}_{-}^0}C$
• D. ${10}^{{}_{-}^0}C$

Answer 1

Answer: (D)

$\theta$ is temperature.

${\theta }_{mix}$ is given by : $=\frac{{\theta }_W-\frac{L_i}{c_W}}{2}$

putting values:

${\theta }_{mix}=\frac{{\theta }_W-\frac{L_i}{c_W}}{2}=\frac{100-\frac{80}{1}}{2}={10}^{\circ }C$