Question

# 1.00kg of 235U undergoes fission process. If energy released per event is 200MeV, then the total energy released is

A
5.12×1024MeV
B
6.02×1023MeV
C
5.12×1026MeV
D
6.02×1026MeV
Solution
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#### M=1 kgNo. of moles =n=1000235=4.2553No. of atoms of U=nNA=2.562×1024 atomsEnergy released per atom =200 MeVTotal energy released =200×2.562×1024=5.12×1026MeV

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