1-00 mole sample of O-2 and 3 moles sample of H-2 are mixed isothermally in a 125-3 L container 125-0C- Gaseous mixture undergoes reaction to from water vapour- Assume ideal gas behaviour total

Solve

Guides

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

1.00 mole sample of $$O_2$$ and 3 moles sample of $$H_2$$ are mixed isothermally in a 125.3 L container at $$125^0C$$. Gaseous mixture undergoes reaction to from water vapour. Assume ideal gas behaviour total

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

1 mol of

O_{2}

and 3 mol of

H_{2}

are mixed isothermally in a

125.3 L

container at

125^{\circ} C

. The gaseous mixture undergoes reaction to form water vapour. Assuming ideal gas behaviour, the total pressure before and after the formation of

H_{2} O (g)

respectively is:

View Solution

Assuming ideal gas behaviour, the $$\Delta S$$ for the isothermal mixing of $$0.8$$ mole $${N}_{2}$$ and $$0.2$$ mole of $${O}_{2}$$ is:

$$\left( \ln { 2 } =0.7,\log { 10 } =2.3 \right) $$

View Solution

When 2 moles of

N_{2}

gas and 9 moles of

H_{2}

gas are mixed and the reaction is completed to form

{NH}_{3}

gas then the reaction mixture will contain:

View Solution

21 g

of nitrogen gas is mixed with 1.2 moles of

S O_{2}

gas and

1.21 \times 10^{23}

molecules of

O_{2}

gas. Find the volume of the gaseous mixture (assuming no reaction) at STP.

View Solution

11 m o l e s

N_{2}

and

12 m o l e s

H_{2}

mixture reacted in

20 L

vessel at

800 K

. After equilibrium was reached,

6 m o l e

H_{2}

was present.

3.58 L

of liquid water is injected in equilibrium mixture and resultant gaseous mixture suddenly cooled to

300 K

. What is the final pressure of gaseous mixture/? Neglect vapour pressure of liquid solution. Assume (i) all

N H_{3}

dissolved in water (ii) no change in volume of liquid (iii) no reaction of

N_{2}

and

H_{2}

300 K

(Given

R = 0.821 L a t m m o l^{- 1} K^{- 1}

)

View Solution