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Question

$1.2 \times 10^{24}$ atoms of iron weighs ______ grams.
$90$
$111.5$
$80$
$70$

A

80

B

70

C

90

D

111.5

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Solution

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For Fe atomic mass $= 56$ g $= 6.023 \times (10)^{23}$ atoms
$1.2 \times 10^{24}$ atoms $= \frac{56}{6.023 \times 10^{23}} \times 1.2 \times 10^{24} = 111.5$ g

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