You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question
13 Hydrogen burns exothermically in oxygen.
The equation for the reaction is:
2H2 + O2 + 2H20
The table shows the bond energies involved.
bond
bond energy in kJ/mol
H-H
436
O=0
498
0-H
464
What is the energy given out curing the reaction?
A
B
c
-3226 kJ/mol
-884 kJ/mol
486 kJ/mol
D
-442 kJ/mol
Open in App
Solution
Verified by Toppr
Was this answer helpful?
1
Similar Questions
Q1
Bond energies of some bonds are given below: Cl-Cl = 242.8 kJ mol−1, H-Cl = 431.8 kJ mol−1, O-H = 464 kJ mol−1, O=O = 442 kJ mol−1 Using the B.E.s given, calculate ΔH for the given reaction: 2Cl2+2H2O→4HCl+O2
View Solution
Q2
Calculate the enthalpy change for the reaction, H2+F2→2HF given that Bond energy of H – H bond = 434 kJ/mol Bond energy of F – F bond = 158 kJ/mol Bond energy of H – F bond = 565 kJ/mol
View Solution
Q3
Energy required to break all four C-H bonds in methane is 1662 kJ/mol. Calculate the average bond enthalpy for methane molecule.
View Solution
Q4
Find the enthalpy of formation of Hydrogen flouride on the basis of following data : Bond energy of H−H=434kJmol−1 Bond energy of F−F=158kJmol−1 Bond energy of H−F=565kJmol−1
View Solution
Q5
From the following bond energies $$H - H $$ bond energy $$ = 420\ KJ\ mol^{-1} $$ $$C = C $$ bond energy $$ = 601\ KJ\ mol^{-1} $$ $$C - C$$ bond energy $$ = 340\ KJ\ mol^{-1} $$ $$C - H $$ bond energy $$ = 425\ KJ\ mol^{-1} $$ Enthalpy for the reaction: $$C_{2} H_{2} + 2H_{2} \rightarrow C_{2} H_{6} $$