18 is divisible by both 2 and 3- It is also divisible by 2times 3-6- Similarly- a number is divisible by both 4 and 6- Can we say that the number must also be divisible by 4times 6-24- If not- give an example to justify your answer-

Question

Toppr Admin · Accepted Answer

No-160-It is not necessary because -12- and -36- are divisible by -4- and -6- both- but are not divisible by -24-

$$18$$ is divisible by both $$2$$ and $$3$$. It is also divisible by $$2\times 3=6$$. Similarly, a number is divisible by both $$4$$ and $$6$$. Can we say that the number must also be divisible by $$4\times 6=24$$? If not, give an example to justify your answer.

No.
It is not necessary because $$12$$ and $$36$$ are divisible by $$4$$ and $$6$$ both, but are not divisible by $$24$$.

$$18$$ is divisible by both $$2$$ and $$3$$. It is also divisible by $$2\times 3=6$$. Similarly, a number is divisible by both $$4$$ and $$6$$. Can we say that the number must also be divisible by $$4\times 6=24$$? If not, give an example to justify your answer.

No. It is not necessary because $$12$$ and $$36$$ are divisible by $$4$$ and $$6$$ both, but are not divisible by $$24$$.

No.
It is not necessary because $$12$$ and $$36$$ are divisible by $$4$$ and $$6$$ both, but are not divisible by $$24$$.