A skateboarder starts from rest and moves down a hill with constant acceleration in a straight line, traveling for $$6 s$$. In a second trial, he starts from rest and moves along the same straight line with the same acceleration for only $$2 s$$. How does his displacement from his starting point in this second trial compare with that from the first trial?
A
one-ninth as large
B
nine times larger
C
one-third as large
D
three times larger
E
$$1/\sqrt{3}$$ times as large
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Solution
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Correct option is C. one-ninth as large With original velocity zero, displacement is proportional to the square of time in $$(1/2)at^{2}$$. Making the time one-third as large makes the displacement one-ninth as large, answer (c).
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