The electric field between two parallel square metal plates is $130 N / C$ . The plates are $0.85 m$ on a side and are separated by $3.0 c m$ . What is the charge on each plate (assume equal and opposite)' Neglect edge effects

Question

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Answer 1

The electric field between two close parallel plates is,

$E = \frac{σ}{ϵ _{0}}$

surface charge density is

$σ = Q / A$

$E = \frac{\frac{Q}{A}}{ϵ _{0}}$ $= \frac{Q}{ϵ _{0} A}$

$Q = ϵ_{0} E A$

$= ϵ_{0} E l^{2}$

$Q = (8.85 \times 1 0^{- 12} C^{2} N . m^{2}) (130 N / C) (0.85 m)^{2}$

$= 8.3 \times 1 0^{- 10} C$

Answer 2

The electric field between two close parallel plates is,

E = \frac{σ}{ϵ _{0}}

surface charge density is

σ = Q / A

E = \frac{\frac{Q}{A}}{ϵ _{0}}

= \frac{Q}{ϵ _{0} A}

Q = ϵ_{0} E A

= ϵ_{0} E l^{2}

Q = (8.85 \times 1 0^{- 12} C^{2} N . m^{2}) (130 N / C) (0.85 m)^{2}

= 8.3 \times 1 0^{- 10} C