1litre of a gas weights 2g at 300K and 1atm pressure.If the pressure is made 0.75atm at which temperature will 1L of same gas weighs 1g ?
600k
900K
800K
450K
A
900K
B
800K
C
600k
D
450K
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Solution
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P1 = 1 atm ; W1 = 2g
P2 = 0.75 atm ; W2 = 1 g
T1 = 300 K ; V1 = 1 L
T2 = ? ; V2 = 1 L
So we know that,
P1V1/P2V2=W1T1/W2T2
Substituting in the above formula we get,
=1×1/0.75×1=2×300/1×T2
=1/0.75=600/T2
Cross Multiplying we get,
=T2×1=600×0.75
=T2=450 K
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