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Question

1 $s^{2} 2 s^{2} 2 p^{6}$ is the electron configuration of:
nitrogen
neon
argon
boron

A

boron

B

argon

C

neon

D

nitrogen

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Solution

Verified by Toppr

Atomic number = 10
$∴ N e = 1 s^{2} 2 s^{2} s p^{6}$
$∴$ Ne is placed in $2^{n d}$ row of periodic
table

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