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"(2) A buoy is made in the form of hemisphere\nsurmounted by a right cone whose circular\nbase coincides with the plane surface of\nhemisphere. The radius of the base of the cone\nis 3\\( \\cdot 5 \\) metres and its volume is two-third of the\nand the surface area of the buoy, correct to\ntwo places of decimal."

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Q1

A toy is made in the form of hemisphere surmounted by a right cone whose circular base coincides with the plane surface of hemisphere. The radius of the base of the cone is

3 \cdot 5 m e t e r s

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Q2

A toy made in the form of hemisphere surmounting by a right cone whose circular base is joined with the plane surface of the hemisphere. The radius of the base of the cone is $$6cm$$ and its volume is $$\dfrac{3}{2}$$ of the hemisphere.
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A toy is in the form of a hemisphere surmounted by a right circular cone of the same base radius as that of the hemisphere.If the radius of the base of the cone is 21 cm and its volume is $\frac{2}{3}$ of the volume of the hemisphere,calculate the height of the cone and the surface area of the toy? $(U s e π = 22 / 7)$

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