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Given: Specific heats of water and ice are 1 kcal kg−1 oC−1 and 0.5 kcal kg−1oC−1 and latent heat of fusion of ice is 80 k cal kg−1.

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Solution

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m′iceL+mice20(0.5)=mW(1)(20)

m′ice80=5×20−2×(20)×0.5=80

∴m′ice=1kg

Hence total amount of water =6kg.

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