2 kg of ice at −20oC is mixed with 5 kg of H2O at 20oC in an insulating vessel having negligible heat capacity. Calculate the final mass of water left in the container. Given: Specific heats of water and ice are 1 kcal kg−1oC−1 and 0.5 kcal kg−1oC−1 and latent heat of fusion of ice is 80 k cal kg−1.
4 kg
2 kg
7 kg
6 kg
A
6 kg
B
2 kg
C
4 kg
D
7 kg
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Solution
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Applying heat lost=heat gained m′iceL+mice20(0.5)=mW(1)(20) m′ice80=5×20−2×(20)×0.5=80 ∴m′ice=1kg Hence total amount of water =6kg.
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