20 persons are invited for a party, then the number of ways in which they and the host be seated at a round table is
20!
21!
22!
2.20!
A
21!
B
22!
C
20!
D
2.20!
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Solution
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Total no. of persons including host are (20+1) As they have to sit in round table, the required permutation is (n−1)! =(20+1−1)! =20!
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