0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

22Ne nucleus, after absorbing energy, decays into two α-particles and an unknown nucleus. The unknown nucleus is
  1. carbon
  2. boron
  3. oxygen
  4. nitrogen

A
oxygen
B
nitrogen
C
boron
D
carbon
Solution
Verified by Toppr

22Ne decays
α particle = He2+
Mass No = 4
p=2,n=2
So, New mass no. =228=14
Atomic No. =104=6
So, the new element is 6C14

Was this answer helpful?
1
Similar Questions
Q1
22Ne nucleus, after absorbing energy, decays into two α-particles and an unknown nucleus. The unknown nucleus is
View Solution
Q2
Ne nucleus, after absorbing energy, decays into two α-particles and an unknown nucleus. The unknown nucleus is:
View Solution
Q3
A moving α particle encounters a stationary unknown nucleus. After collision the two nuclei are scattered in mutually perpendicular directions. If some kinetic energy is lost in collision then unknown nucleus must be
View Solution
Q4
Initially, the nucleus of Radium226 is at rest. It decays by emitting an α particle, and thus the nucleus of Radon is created. The released energy during the decay is 4.87 MeV, which appears as the kinetic energy of the two resulted particles. The kinetic energy of α particle & Radon nucleus are respectively.
[mα=4.002 u, mRn=222.017 u]
View Solution
Q5
A nucleus of mass 218 amu in free state decays to emit an α particle. Kinetic energy of the α particle emitted is 6.7 MeV. The recoil energy (in MeV) of the daughter nucleus is:
View Solution