You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question
23. Let \( f ( x ) = \operatorname { sgn } \left( \cot ^ { - 1 } x \right) + \tan \left( \frac { \pi } { 2 } [ x ] \right) , \) where \( \lfloor x | \) is the greatest integer function less than or equal to \( x \) . Then
which of the following afternatives is/are true? \( f ( x ) \) is many-one but not an even function b. \( f ( x ) \) is a periodic function (. Fx) is a bounded function.
d. The graph of \( f ( x ) \) remains above the \( x \) -axis.
Open in App
Solution
Verified by Toppr
Was this answer helpful?
0
Similar Questions
Q1
Let f(x) be a real valued function defined on: R→R such that f(x)=[x]2+[x+1]−3, where [x] denotes greatest integer less than or equal to x, then which of the following option(s) is/are correct?
View Solution
Q2
Period of f(x)=sgn([x]+[−x]) is equal to (where [.] denotes greatest integer function)
View Solution
Q3
Let $$F(x)$$ be a function defined by $$F(x)=x-[x], 0\neq x \in R$$, where $$[x]$$ is the greatest integer less than or equal to $$x$$. Then the number of solutions of $$F(x)+F(1/x)=1$$ is/are
View Solution
Q4
Let f(x)=[x]+1{x}+1,forf:[0,52)→(12,3] where [x] denotes greatest integer function and {x} denotes fractional part function, then which of the following is/are true?
View Solution
Q5
Let f(x) be a function defined by f(x)=x−[x],x∈R−{0} where [x] is the greatest integer less than or equal to x. Then the number of solutions of f(x)+f(1x)=1 are :