25 ml of H2O2 solution were added to excess of acidified KI solution. The iodine so liberated required 20 ml of 0.1NNa2S2O3 for titration. Calculate strength of H2O2 in terms of normality and percentage?
0.04N,0.163%
0.08N,0.136%
0.02N,0.163%
0.04N,0.136%
A
0.08N,0.136%
B
0.04N,0.163%
C
0.02N,0.163%
D
0.04N,0.136%
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Solution
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I2+2Na2S2O−3→Na2S4O6+2NaI
Milliequivalent of H2O2= Milliequivalent of I2=Milliequivalent of Na2S2O3
w34/2×1000=20×0.1
∴WH2O2=0.034 gm/25 ml
NH2O2=0.03434/2×100025=0.08
Volume strength =5.6×0.08=0.448
% strength =1756×5.6×0.08=0.136.
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