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Correct option is B)

$27Γ34βΟr_{3}=34βΟR_{3}$

where, $r$ and $R$ are the volume of smaller and bigger sphere respectively.

$βR=3r$

Now, initial potential of smaller sphere,

$V_{1}=41βΟΟ΅_{0}rQβ$

$β΄Q=V_{1}rΓ4ΟΟ΅_{0}$

$β΄$ Charge on $27$ spheres, we have

$Q_{T}=27Γ10ΓrΓ4ΟΟ΅_{0}$

Now, charge on bigger sphere

$Q_{B}=V_{2}RΓ4ΟΟ΅_{0}$

Now, $Q_{T}=Q_{B}$

$β270ΓrΓ4ΟΟ΅_{0}=V_{2}RΓ4ΟΟ΅_{0}$

$β270r=V_{2}Γ3rβV_{2}=90ΒV$.

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