2NOBr-g-rightleftharpoons2NO-g-Br-2-g- If nitrosyl bromide -NOBr- is 33-33 per dissociated 25-circ-C- a total pressure of 0-28 atm- Calculate K-p- the dissociation this temperature-K-p-0-01 atmK-p-0-31 atmK-p-0-03 atmK-p-0-04 atm

Question

2NOBr-g-rightleftharpoons2NO-g-Br-2-g-  If nitrosyl bromide -NOBr- is 33-33 per dissociated  25-circ-C- a total pressure of 0-28 atm- Calculate K-p- the dissociation this temperature-K-p-0-01 atmK-p-0-31 atmK-p-0-03 atmK-p-0-04 atm

Toppr Admin · Accepted Answer

2NOBr-g-x2192-2NO-g-Br2-g-xA0- -xA0- -xA0-1-2x -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- 2x -xA0- -xA0- -xA0- -xA0- -xA0-xA0-xA0-xKp-2x-1-x-2P2-xD7-x-1-x-P-1-x2212-2x-1-x-P2-0-01 atm-xA0-where P is 0-28 atm-

$2 N O B r (g) ⇌ 2 N O (g) + B r_{2} (g) .$ If nitrosyl bromide (NOBr) is 33.33 per dissociated at $25^{\circ} C$ & a total pressure of 0.28 atm. Calculate $K_{p}$ for the dissociation at this temperature.
$K_{p} = 0.01 a t m$
$K_{p} = 0.31 a t m$
$K_{p} = 0.03 a t m$
$K_{p} = 0.04 a t m$

$2 N O B r (g) \to 2 N O (g) + B r_{2} (g)$
1-2x 2x x
$K_{p} = (2 x / 1 + x)^{2} P^{2} \times (x / 1 + x) P / (1 - 2 x / 1 + x) P^{2} = 0.01$ atm, where P is 0.28 atm.

2NOBr(g)⇌2NO(g)+Br2(g). If nitrosyl bromide (NOBr) is 33.33 per dissociated at 25∘C& a total pressure of 0.28 atm. Calculate Kp for the dissociation at this temperature.Kp=0.01atmKp=0.31atmKp=0.03atmKp=0.04atm

2NOBr(g)→2NO(g)+Br2(g) 1-2x 2x xKp=(2x/1+x)2P2×(x/1+x)P/(1−2x/1+x)P2=0.01 atm, where P is 0.28 atm.

$2 N O B r (g) ⇌ 2 N O (g) + B r_{2} (g) .$ If nitrosyl bromide (NOBr) is 33.33 per dissociated at $25^{\circ} C$ & a total pressure of 0.28 atm. Calculate $K_{p}$ for the dissociation at this temperature.
$K_{p} = 0.01 a t m$
$K_{p} = 0.31 a t m$
$K_{p} = 0.03 a t m$
$K_{p} = 0.04 a t m$

$2 N O B r (g) \to 2 N O (g) + B r_{2} (g)$
1-2x 2x x
$K_{p} = (2 x / 1 + x)^{2} P^{2} \times (x / 1 + x) P / (1 - 2 x / 1 + x) P^{2} = 0.01$ atm, where P is 0.28 atm.