0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

"3) \\( - 1 \\leq a \\leq 1 \\)\nThe mean and the variance of a binomial distribution are 4 and 2 respectively. Then the\nprobability of atleast 2 successes is\n\\( \\begin{array} { l l l l } { \\text { 1) } 37 / 256 } & { \\text { 2) } 247 / 256 } & { \\text { 3) } 128 / 256 } & { \\text { 4) } 219 / 256 } \\end{array} \\)"

Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
If the mean and variance of a binomial distribution are 4 and 2, respectively. Then, the probability of atleast 7 successes is
View Solution
Q2

The mean and variance of a binomial distribution are 4 and 2 respectively. Then the probability of 2 successes is


View Solution
Q3
The mean and the variance of a binomial distribution are 4and 2 respectively. Then the probability of 2 successes is:
View Solution
Q4
If the mean and variance of a binomial distribution are 4 and 2 respectively, then the probability of 2 successes of that binomial variate X, is
View Solution
Q5
The mean and variance of Binomial Distribution are 4 and 2 respectively, then the probability of success is
View Solution