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Question

33x3+y3 is equal to
  1. (3x+y)(3x23xy+y2)
  2. (3xy)(3x2+3xy+y2)
  3. (3x+y)(3x2+3xy+y2)
  4. (3xy)(3x23xyy2)

A
(3xy)(3x2+3xy+y2)
B
(3x+y)(3x2+3xy+y2)
C
(3xy)(3x23xyy2)
D
(3x+y)(3x23xy+y2)
Solution
Verified by Toppr

Given, 33x3+y3=(3x)3+y3
Since, x3+y3=(x+y)(x2+y2xy)
(3x)3+y3=(3x+y)((3x)2+y23xy)
=(3x+y)(3x2+y23xy)
=(3x+y)(3x23xy+y2)
Option A is correct.

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