$$30^{0}$$ is one-half of its complement.
Correct option is A. True
Let $$x$$ and $$y$$ are two angles making a complementary angles, and $$x$$ is $$30^o$$.
Then,
$$\implies$$ $$x+y=90^o$$
$$\implies$$ $$30^o+y=90^o$$
$$\implies$$ $$y=90^o-30^o=60^o$$
$$\implies$$ $$y=60^o$$.
Clearly, $$x$$ is half of its complement $$y$$.That is, $$30^o=\dfrac{1}{2}\times60^o$$ and is true.
Hence, the statement is true and option $$A$$ is correct.