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Work Done by a Variable Force
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300 J of work is done in sliding a 2 kg
Question
3
0
0
J
of work is done in sliding a
2
k
g
block up an inclined plane of height
1
0
m
. The work done against friction is (Take
g
=
1
0
m
/
s
2
)
A
zero
B
1
0
0
J
C
2
0
0
J
D
3
0
0
J
Medium
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Solution
Verified by Toppr
Correct option is B)
Step 1: Draw the free body diagram
Step 2: Write the equation for work done
Let
W
f
be the work done against friction
The total work done on a particle is equal to the change in its mechanical energy
W
=
W
f
+
P
E
=
W
f
+
m
g
h
.
.
.
.
.
.
.
.
(
1
)
Step 3: Work done against the friction
From equation (1)
W
f
=
W
−
m
g
h
Substituting the values :
W
f
=
3
0
0
J
−
(
2
k
g
×
1
0
m
/
s
2
×
1
0
m
)
=
1
0
0
J
Hence option
(
B
)
is correct.
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