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Standard XII
Physics
NCERT
Question
A magnet of magnetic moment
50
^
i
A
m
2
is placed along the x-axis in a magnetic field
→
B
=
(
0.5
^
i
+
3.0
^
j
)
T
. The torque acting on the magnet is
175
^
k
N
−
m
150
^
k
N
−
m
75
^
k
N
−
m
25
√
37
^
k
N
−
m
A
75
^
k
N
−
m
B
150
^
k
N
−
m
C
25
√
37
^
k
N
−
m
D
175
^
k
N
−
m
Open in App
Solution
Verified by Toppr
→
m
=
50
^
i
A
m
2
→
B
=
(
0.5
^
i
+
30
^
j
)
T
→
z
=
→
m
×
→
B
=
50
^
l
×
c
0.5
^
i
+
3.0
^
j
=
50
×
3
k
=
150
^
k
N
m
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