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Question

A magnet of magnetic moment 50^iAm2 is placed along the x-axis in a magnetic field B=(0.5^i+3.0^j)T. The torque acting on the magnet is
  1. 175^kNm
  2. 150^kNm
  3. 75^kNm
  4. 2537^kNm

A
75^kNm
B
150^kNm
C
2537^kNm
D
175^kNm
Solution
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m=50^iAm2
B=(0.5^i+30^j)T
z=m×B
=50^l×c0.5^i+3.0^j
=50×3k
=150^kNm

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