Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

$_{19}^{39} K$ and $_{20}^{40} C a$ are :
Isotopes
Isobars
Isotones
Isodiaphers

A

Isobars

B

Isotones

C

Isodiaphers

D

Isotopes

Open in App

Solution

Verified by Toppr

No. of neutron in K $= 39 - 19 = 20$
No. of neutron in Ca $= 40 - 20 = 20$

Was this answer helpful?

0

Similar Questions

Q1

_{19}^{39} K

and

_{20}^{40} C a

are :

View Solution

Q2

Which of the following are isobars?

$_{18}^{40} A r$ $_{6}^{14} C$ $_{20}^{40} C a$ $_{7}^{14} N$

View Solution

Q3

The binding energy per nucleon of

_{20}^{40} C a

is

- ------- -

(

_{20}^{40} C a =

39.962589 amu,

m_{p} =

1.007825 amu;

m_{n} =

1.008665 a m u

and

1 a m u

is equivalent to

931.5 M e V

)

View Solution

Q4

In a radioactive sample

_{19}^{40} K

nuclei either decay into stable

_{20}^{40} C a

nuclei with decay constant

4.5 \times 10^{- 10}

per year or into stable

_{18}^{40} A r

nuclei with decay constant

0.5 \times 10^{- 10}

per year. Given that in this sample all the stable

_{20}^{40} C a

and

_{18}^{40} A r

nuclei are produced by the

_{19}^{40} K

nuclei only. In time

t \times 10^{9}

years, if the ratio of the sum of stable

_{20}^{40} C a

and

_{18}^{40} A r

nuclei to the radioactive

_{19}^{40} K

nuclei is

99

, the value of t will be? [Given: In

10 = 2.303

]

View Solution

Q5

Assertion :It is esay to remove a proton from

_{20}^{40} C a

nucleus as compared to a neutron Reason: Inside nucleus neutrons are acted on only by attractive forces but photons are also acted on by repulsive forces

View Solution