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Standard VI
Mathematics
Addition of Fractions
Question
[
3
1
4
÷
{
1
1
4
−
1
2
(
2
1
2
−
1
4
−
1
6
)
}
]
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Solution
Verified by Toppr
[
3
1
4
÷
(
1
1
4
−
1
2
(
2
1
2
−
1
4
−
1
6
)
)
]
=
3
1
4
÷
[
5
4
−
1
2
(
5
2
−
1
4
−
1
6
)
]
=
13
4
÷
[
5
4
−
5
4
+
1
8
+
1
12
]
=
13
4
÷
[
1
8
+
1
12
]
=
13
4
÷
5
24
=
13
4
×
24
5
=
78
5
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Similar Questions
Q1
[
3
1
4
÷
{
1
1
4
−
1
2
(
2
1
2
−
1
4
−
1
6
)
}
]
View Solution
Q2
Simplify :
[
3
1
4
÷
{
1
1
4
−
1
2
(
2
1
2
−
1
4
−
1
6
)
}
]
÷
(
1
2
o
f
4
1
3
)
View Solution
Q3
Evaluate :
1
2
+
3
1
4
+
1
1
6
2
1
2
+
1
1
6
+
6
1
3
+
1
120
View Solution
Q4
Find the value of:
(1)
(2)
(3)
(4)
(5)