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Question

(3x+4)2=
  1. 9x2+16
  2. 9x2+116
  3. 19x2+16
  4. 19x2+24x+16
  5. 19x2+12x+16

A
9x2+16
B
9x2+116
C
19x2+12x+16
D
19x2+16
E
19x2+24x+16
Solution
Verified by Toppr

We meed to expand (3x+4)2
It can written as 1(3x+4)2
Now by using (a+b)2=a2+2ab+b2, we get
(3x+4)2=9x2+16+24x
So, (3x+4)2=19x2+16+24x

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