4 moles of HI is taken in a liter closed vessel and heated to equilibrium. At equilibrium, the concentration of H2 is one mollit−1.
Then the equilibrium constant is:
4
0.5
0.25
2
A
4
B
0.5
C
2
D
0.25
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Solution
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The equilibrium reaction is H2(g) + I2(g)⇌2HI(g).
The number of moles of various species presents initially, and at equilibrium, are given in the following table.
HI
H2
I2
Initial
4
0
0
change
-2
1
1
equilibrium
4-2=2
1
1
The expression for the equilibrium constant is Kc=[H2][I2][HI]2.
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