A right circular cylinder is $$3m$$ high and the circumference of its base is $$22 m$$. Find its curved surface area.
Given: Circumference of base of cylinder $$= 22 m$$
height of cylinder $$= 3m$$
$$\because$$ Circumference of base $$= 2 \pi r$$ [$$r$$ is the radius]
$$22 = 2 \times \dfrac{22}{7} \times r$$
$$\Rightarrow r = \dfrac{7}{2} m$$
Curved surface area of cylinder $$= 2 \pi rh$$
$$= 2 \times \dfrac{22}{7} \times \dfrac{7}{2} \times 3 = 66 m^2$$
$$\boxed{\text{Hence, curved surface area is } 66 m^2}$$