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Question
5
0
g
of an alloy of gold and silver contains
8
0
%
gold(by weight). The quantity of gold, that is to be mixed up with this alloy, so that it may contain
9
5
%
gold, is:
A
2
0
0
g
B
1
5
0
g
C
5
0
g
D
1
0
g
Medium
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Solution
Verified by Toppr
Correct option is B)
5
0
g
of gold contains
8
0
% of gold.
Hence amount of gold
=
1
0
0
8
0
×
5
0
=
2
8
0
=
4
0
g
So,
5
0
+
x
4
0
+
x
=
1
0
0
9
5
=
2
0
1
9
2
0
(
4
0
+
x
)
=
1
9
(
5
0
+
x
)
8
0
0
+
2
0
x
=
9
5
0
+
1
9
x
2
0
x
−
1
9
x
=
9
5
0
−
8
0
0
x
=
1
5
0
g
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