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$50$
$g$
of an alloy of gold and silver contains
$80$
$%$
gold(by weight). The quantity of gold, that is to be mixed up with this alloy, so that it may contain
$95$
$%$
gold, is:
A
$200$
$g$
B
$150$
$g$
C
$50$
$g$
D
$10$
$g$
Medium
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Solution
Verified by Toppr
Correct option is B)
$50g$
of gold contains
$80$
% of gold.
Hence amount of gold
$=10080 ×50=280 =40g$
So,
$50+x40+x =10095 =2019 $
$20(40+x)=19(50+x)$
$800+20x=950+19x$
$20x−19x=950−800$
$x=150g$
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