Correct option is A. 88
Let $$x$$ be the number of cows that can graze the field in $$10$$ days.
Number of days | $$16$$ | $$10$$ |
Number of cows | $$55$$ | $$x$$ |
Since, the number of cows and the number of days taken by them to graze the field are in inverse variation, we have:$$\Rightarrow$$ $$16\times 55=10\times x$$
$$\Rightarrow$$ $$x=\dfrac{16\times 55}{10}$$
$$\Rightarrow$$ $$x=88$$
$$\therefore$$ The required number of cows is $$88.$$