60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, then the amount of tin in the new alloy is
36 kg
44 kg
53 kg
80 kg
A
36 kg
B
80 kg
C
44 kg
D
53 kg
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Solution
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Alloy A has tin=25×60=24Kg Alloy B has tin=15×100=20Kg Then alloy C(A+B) has tin=24+20=44Kg
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