60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, then the amount of tin in the new alloy is

A

36 kg

B

44 kg

C

53 kg

D

80 kg

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Solution

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Correct option is B)

Alloy A has tin=$52 ×60=24Kg$ Alloy B has tin=$51 ×100=20Kg$ Then alloy C(A+B) has tin=$24+20=44Kg$