60 kg of an alloy X is mixed with 100 kg of an alloy Y- If alloy X has lead and tin in the ratio of 3 - 2 and alloy Y has tin and copper in the ratio of 1 - 4- then the amount of tin in the new alloy is44 kgs-36 kgs-53 kgs-80 kgs-

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Toppr Admin · Accepted Answer

Total amount of tin in alloy x and y2x5-15y-25-xD7-60-15-xD7-100-24-20-44-xA0-kg-

$60 k g$ of an alloy $X$ is mixed with $100$ kg of an alloy $Y$ . If alloy $X$ has lead and tin in the ratio of $3 : 2$ and alloy $Y$ has tin and copper in the ratio of $1 : 4$ , then the amount of tin in the new alloy is
$44 k g s .$
$36 k g s .$
$53 k g s .$
$80 k g s .$

Total amount of tin in alloy $x$ and $y$
$\frac{2 x}{5} + \frac{1}{5} y$
$= \frac{2}{5} \times 60 + \frac{1}{5} \times 100$
$= 24 + 20 = 44 k g$ .

60 kg of an alloy X is mixed with 100 kg of an alloy Y. If alloy X has lead and tin in the ratio of 3:2 and alloy Y has tin and copper in the ratio of 1:4, then the amount of tin in the new alloy is44 kgs.36 kgs.53 kgs.80 kgs.

Total amount of tin in alloy x and y2x5+15y=25×60+15×100=24+20=44 kg.

$60 k g$ of an alloy $X$ is mixed with $100$ kg of an alloy $Y$ . If alloy $X$ has lead and tin in the ratio of $3 : 2$ and alloy $Y$ has tin and copper in the ratio of $1 : 4$ , then the amount of tin in the new alloy is
$44 k g s .$
$36 k g s .$
$53 k g s .$
$80 k g s .$

Total amount of tin in alloy $x$ and $y$
$\frac{2 x}{5} + \frac{1}{5} y$
$= \frac{2}{5} \times 60 + \frac{1}{5} \times 100$
$= 24 + 20 = 44 k g$ .