64 small drops of mercury each of radius r and change q coalesce to from a big drop. The ratio of the surface charge density of each small drop with that of big drop is:

4:1

1:4

1:64

64:1

A

4:1

B

1:4

C

64:1

D

1:64

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Solution

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Formulae:

σsmallσbig=qQ×R2r2

=qnq×(n13r)2r2

=n−13

=64−13

=14

hence the ratio is 1:4

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