0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

64 small drops of mercury each of radius r and change q coalesce to from a big drop. The ratio of the surface charge density of each small drop with that of big drop is:4:11:41:6464:1

A
4:1
B
1:4
C
64:1
D
1:64
Solution
Verified by Toppr

Formulae:σsmallσbig=qQ×R2r2=qnq×(n13r)2r2=n−13=64−13=14hence the ratio is 1:4

3
Similar Questions
Q1
64 small drops of mercury each of radius r and change q coalesce to from a big drop. The ratio of the surface charge density of each small drop with that of big drop is:
View Solution
Q2
64 droplets of mercury each of radius r and carrying charge q, coalesce to form a big drop. Compare the surface density of charge of each drop with is that of the big drop.
View Solution
Q3
n charged drops, each of radius r and charge q, coalesce to form a big drop of radius R and charge Q. If V is the electric potential and E is the electric field at the surface of a drop, then
View Solution
Q4
Eight small drops, each of radius r and having same charge q are combined to form a big drop. The ratio of potential of the bigger drop to the smaller drop is
View Solution
Q5
1000 small water drops each of radius r and charge q coalesce together to one spherical drop. The potential of the big drop is larger than that of the smaller drops by a factor of:
View Solution
Solve
Guides