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Question

64 small drops of mercury each of radius r and change q coalesce to from a big drop. The ratio of the surface charge density of each small drop with that of big drop is:
  1. 4:1
  2. 1:4
  3. 1:64
  4. 64:1

A
4:1
B
1:4
C
64:1
D
1:64
Solution
Verified by Toppr

Formulae:

σsmallσbig=qQ×R2r2

=qnq×(n13r)2r2

=n13

=6413

=14

hence the ratio is 1:4

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