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7 moles of a tetra-atomic non-linear gas A at 10atm and TK are mixed with 6 moles of another gas B at T/3K and 5atm in a closed, rigid vessel without energy transfer with surroundings. If final temperature of mixture was 5T/6K, then atomcity of gas B is (Assuming all modes of energy are active)

Solution
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Cv of gas A=32R+32R+6R=9R
Let Cv of gas B=X
Heat lost by gas A=7×9R×(T5T6)
Heat gained by gas B=6X(5T6T3)
63R(T6)=6X(T2)=X=72R
gas is diatomic.
and atomcity of gas is 2.

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