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\( 8 , \) If \( x ^ { 2 } + \frac { 1 } { n ^ { 2 } } = 7 \) and \( x \neq 0 ; \) find the value of \( 7 x ^ { 3 } + 8 x - \frac { 7 } { x ^ { 3 } } - \frac { 8 } { x } \)

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Similar Questions

Q1

If

x^{2} + \frac{1}{x^{2}} = 7

and

x \neq 0

; find the value of :

7 x^{3} + 8 x - \frac{7}{x^{3}} - \frac{8}{x}

.

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Q2

If

x^{2} + \frac{1}{x^{2}} = 7

and

x \neq 0

; find the value of :

7 x^{3} + 8 x - \frac{7}{x^{3}} - \frac{8}{x}

View Solution

Q3

8 x + 7 = 0

\Rightarrow 8 x = - 7 + 0

\Rightarrow 8 x = - 7

\Rightarrow x = 8 + 7

The error in solving linear equation

8 x + 7 = 0

is .

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Q4

If x² + 1/x² =7,x is greater than 0; find the value of
a) x³ + 1/x³ and
b) x - 1/x

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Q5

The solution of

\frac{d^{3} y}{d x^{3}} - 8 \frac{d^{2} y}{d x^{2}} = 0

satisfying

y (0) = \frac{1}{8}, y^{1} (0) = 0

and

y^{2} (0) = 1

is [here

y^{n} (x) = \frac{d^{n} y}{d x^{n}}]

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