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$_{80}^{197} H g$ decays to $_{79}^{197} A u$ through electron capture with a decay constant of 0.257 per day. (a) What other particle or particles are emitted in the decay ? (b) Assume that the electron is captured from the K shell . Use Meseley,s law $\sqrt{v} = a (Z - b)$ with a = 4.95 $\times 10^{7}$ $s^{- 1 / 2}$ and b = 1 to find the wavelength of the $K_{α}$ X-ray emitted following the electron capture.

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Similar Questions

Q1

_{80}^{197} H g

decays to

_{79}^{197} A u

through electron capture with a decay constant of 0.257 per day. (a) What other particle or particles are emitted in the decay ? (b) Assume that the electron is captured from the K shell . Use Meseley,s law

\sqrt{v} = a (Z - b)

with a = 4.95

\times 10^{7}

s^{- 1 / 2}

and b = 1 to find the wavelength of the

K_{α}

X-ray emitted following the electron capture.

View Solution

Q2

{}_{80}^{197}{Hg}

decay to

{}_{79}^{197}{Au}

through electron capture with a decay constant of 0.257 per day. (a) What other particle or particles are emitted in the decay? (b) Assume that the electron is captured from the K shell. Use Moseley's law √v = a(Z − b) with a = 4.95 × 10⁷ s⁻¹^/2 and b = 1 to find the wavelength of the K_α X-ray emitted following the electron capture.

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Q3

In an electron capture, electron from K shell falls into a nucleus to undergo beta decay.

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Q4

The decay constant of

_{80}^{197} H g

(electron capture to

_{79}^{197} A u

) is

1.8 \times 10^{- 4} s^{- 1}

. (a) What is the half-life? (b) What is the average-life? (c) How much time will it take to convert

25

% of this isotope of mercury into gold?

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Q5

The decay constant of $_{80}^{197} Hg$ (electron capture to $_{79}^{197} Au$ ) is 1.8 $\times 10^{- 4} S^{- 1}$ . (a) What is the half-life ? (b) What is the average - life ? (c) How much time will it take to convert $25 %$ of this isotope of mercury into gold ?

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