A 0-5kg ball moving with a speed of 12m-s strikes a hard wall an angle of -30-o- with the wall- It is reflected with the same speed and the same angle- as shown in figure- If the ball is in contact with the wall 0-25s the average force acting on the wall is96N48N24N12N

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Toppr Admin · Accepted Answer

Favg-m-vf-x2212-vi-tvf-0m-svi-12m-sTherefore-Favg-m-vf-x2212-vi-t-xA0- -xA0- -xA0- -xA0- -xA0-0-5-0-x2212-12-0-25-xA0- -xA0- -xA0- -xA0- -xA0-x2212-24N

A 0.5kg ball moving with a speed of 12m/s strikes a hard wall at an angle of 30o with the wall. It is reflected with the same speed and at the same angle, as shown in figure. If the ball is in contact with the wall for 0.25s the average force acting on the wall is96N48N24N12N

Favg=m(vf−vi)/tvf=0m/svi=12m/sTherefore,Favg=m(vf−vi)/t =0.5(0−12)/0.25 =−24N

$F_{a v g} = m (v_{f} - v_{i}) / t$
$v_{f} = 0 m / s$
$v_{i} = 12 m / s$
Therefore,
$F_{a v g} = m (v_{f} - v_{i}) / t$
$= 0.5 (0 - 12) / 0.25$
$= - 24 N$