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Question

A $100 w a t t$ bulb is connected to $200 v o l t s$ main. The resistance of the filament of the bulb is
$400 o h m$
$100 o h m$
$200 o h m$
$50 o h m$

A

200 o h m

B

400 o h m

C

100 o h m

D

50 o h m

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Solution

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Power in resistor is given by
$P = \frac{V^{2}}{R}$
$P = 100 W a t t$ $V = 200 V o l t s$
$∴ R = \frac{V^{2}}{P} = \frac{200 \times 200}{100} = 400 o h m$ .

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